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A solid sphere of radius 3 cm is melted to form a hollow right circular cylindrical tube of length 4 cm and external radius 5 cm. The thickness of the tube is
1 cm
9 cm
0.6 cm
1.5 cm
Volume of Both solids should be equal ∴(4/3)πr^3s=π(R^2−r^2)h 4/3×3^3=(5^2−r^2)4 4×9=(25−r^2)4 25−r^2=9 r^2=16 r=4 thickness of tube = 5 - 4 = 1cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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