send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The area of a rhombus having one side 10 cm and one diagonal 12 cm is
48 cm2
96 cm2
144 cm2
192 cm2
The diagonals in a rhombus are perpendicular , and bisect each other Given length of side is 10 cm and one diagonal as 12 cm we can find the length of other diagonal From the above figure let DB be the 12 cm diagonal,now OB and OD are 6 cm Now consider triangle AOB ,this is a right andled triangle and we know AB=10cm and OB=6cm ,using Pythagoras theorem we can find out lenth of OA as 8cm ,so length of diagonal AC is 2*8=16cm Area of rhombus is product of diagonal divided by 2, 16*12/2=96 sq.cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
Access to prime resources
New Courses