X can do 1 4 of a work in 10 days y can do 40 of the work in 40 days and z can do 1 3 of the work in...........

Quantitative Aptitude (CGL) Time and work

X can do 1/4 of a work in 10 days,y can do 40% of the work in 40 days and z can do 1/3 of the work in 13 days.who will complete the work first

ALL ARE SAME

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Explanation:

Given that x can do 1/4 of work in 10 days
10 days = 1/4 of the work
1 day = 1/4 ÷ 10 = 1/40 of the work
1/40 of the work = 1 day
40/40 of the work = 1 x 40 = 40 days
Given y can do 40% of the work in 40 days
40 days = 40/100 of the work
1 day = 40/100 ÷ 40 = 1/100 of the work
1/100 of the work = 1 day
100/100 of the work = 1 x 100 = 100 days
Given that z can do 1/3 of the work in 13 days
13 days = 1/3 of the work
1 day = 1/3 ÷ 13 = 1/39 of the work
1/39 of the work = 1 day
39/39 of the work = 1 x 39 = 39 days
Answer: z will complete the work first