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What is the sum of first 40 terms of 1 + 3 + 4 + 5 + 7 + 7 + 10 + 9 + ….?
1010
1115
1030
1031
S1=1+4+7+10+…( AP with A1=1,D1=3) S2=3+5+7+9+...(AP with A2=3,D2=2) Sum of 40 terms of the original series = Sum of 20 terms of S1+ Sum of 20 terms of S2 S=N[2A1+(N−1)D1]/2+N[2A2+(N−1)D2]/2 ?S=[20∗((2∗1)+(19∗3))]+[20∗((2∗3)+(19∗2)]/2 ?S=10∗[59+44]=1030
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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