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he angle of depression of the top and bottom of a building 50 M high as observed from top of a tower are 30 degree and 60 degree respectively find the height of the tower and also the horizontal distance between the building and the tower.
20√3
30√3
40√3
50√3
Here CD is the tower and AB is the pole. In ?CDB, CD/BC = tan 60° => 50m/BC = √3 => BC = 50/√3m AE = BC AE = 50/√3m In ?ADE, DE/AE = tan 45° => DE/50/√3m = 1 => DE = 50/√3m so the height of the pole is 50/√3
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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