A and B can do a job in 18 days B and C in 24 days and A and C in 36 days In how many days can C do ...........

Quantitative Aptitude (CGL) Time and work

Download Solution PDF

A and B can do a job in 18 days, B and C in 24 days, and A and C in 36 days. In how many days can C do the work alone?

28.8

120

छोटे Courses बड़े Results

Master Time and work

Prepare through Micro-courses

Try Now

Explanation:

Let Total Work = LCM(18,24,36) = 72 units
A + B = 4 units per day
B + C = 3 units per day
A + C = 2 units per day
Add all three equations :
2(A + B + C) = 9
=> A + B + C = 9/2
=> C = 9/2 - (A + B) = 9/2 - 4 = 1/2
=> C alone can complete the work alone in 72/(1/2) = 144 days.
A alone = 9/2 - 3 = 3/2 per day or 72/(3/2) = 48 days.
B alone = 9/2 - 2 = 5/2 per day or 72/(5/2) = 28.8 days.