send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A right prism has a square base with side of base 4 cm and the height of prism is 9 cm. The prism is cut in three parts of equal heights by two planes parallel to its base. What is the ratio of the volume of the top, middle and the bottom part respectively?
1 : 8 : 27
1 : 7 : 19
1 : 8 : 20
1 : 7 : 20
Pyramid has a square base of side 4 cm. Height of the prism is 9 cm. = > Slant height of the pyramid^2 = ( 9 cm )^2 + ( 4 / 2 cm )^2 = > Slant height of the pyramid^2 = 81 cm^2 + 4 cm^2 = > Slant height of the pyramid^2 = 85 cm^2 When pyramid is cut in three parts of equal height, height of each part becomes ( 9 / 3 ) cm i.e. 3 cm.Also, length of slope of each part becomes √85 / 3 cm i.e. √( 85 / 9 ) cm. Thus, = > Half of length of base of 1st part i.e. pyramid of height 3 cm = √[ √{ 85 / 9 } cm )^2 - ( 3 cm )^2 } = > Length of base of 1st part = 2 x √{ 85 / 9 cm^2 - 9 cm^2 } = > Length of base of 1st part = 2 x √{ ( 85 - 81 ) / 9 } = > Length of base of 1st part = 2 x √{ 4 / 9 } = > Length of base of 1st part = 2 x 2 / 3 Slant height of pyramid is √85. So, slant height of pyramid in 1st part is 2 / 3 of √85 that is √( 340 / 9 ). So, length of base of 2nd pyramid of height 6 cm is 2 x 4 / 3 cm. Thus, = > Required ratio = > 1 / 3 x ( length x breadth x height ) of 1st part : 1 / 3 x ( length x breadth x height ) of 2nd part : 1 / 3 x ( length x breadth x height ) of 3rd part = > ( length x breadth x height ) of 1st part : { ( length x breadth x height ) of 2nd and 1st part - ( length x height x breadth ) of 1st part } : { ( length x breadth x height ) of 3rd part, 2nd part and 1st part ) - ( length x height x breadth ) of 2nd and 1st part } = > { ( 2 x 2 / 3 ) x ( 2 x 2 / 3 ) x 3 } : [ ( 2 x 4 / 3 x 2 x 4 / 3 x 6 ) - ( 2 x 2 / 3 x 2 x 2 / 3 x 3 ) ] : [ 4 x 4 x 9 - ( 2 x 4 / 3 x 2 x 4 / 3 x 6 ) ] = > 16 / 3 : ( 128 / 3 - 16 / 3 ) : ( 144 - 128 / 3 ) = > 64 : 112 : 304 = > 1 : 7 : 19 Hence the required ratio is 1 : 7 : 19.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
Access to prime resources
New Courses