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The cost of 10 pears, 8 guavas and 6 mangoes is Rs. 44. If the cost of each of the fruits, in rupees, is a natural number and cost of no two fruits is the same, find the cost of 4 mangoes and 3 guavas.
Rs.17
Rs.18
Rs.14
Cannot be determined
- Let’s call the cost of a pear = P, guava = G, and mango = M.
- From the given: 10P + 8G + 6M = 44.
- Each fruit cost is a natural number, all are different.
- Since all are natural numbers, let's try small values so that the sum is 44.
- P, G, M must be all different and minimal; let's test logical values:
- Assume pears are the cheapest. Try P = 1: 10*1 + 8G + 6M = 44 ? 8G + 6M = 34.
Let's try G = 2: 8*2 = 16, 34-16=18, so 6M=18?M=3 (All numbers 1,2,3 and different—possible).
Sum: (10*1) + (8*2) + (6*3) = 10 + 16 + 18 = 44
Therefore, P=1, G=2, M=3.
- Cost for 4 mangoes + 3 guavas: 4M + 3G = 4*3 + 3*2 = 12 + 6 = 18.
Option 2, Rs. 18 is correct.
By: Parvesh Mehta ProfileResourcesReport error
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