A train departs Kolkata at 6 a m at a speed of 40 kmph After one hour another train departs Kolkata ...........

Quantitative Aptitude ( CCS) Time & distance

A train departs Kolkata at 6 a.m. at a speed of 40 kmph. After one hour, another train departs Kolkata in the same direction as that of the first train at a speed of 50 kmph. When and at what distance from Kolkata do the two trains meet?

10 a.m. & 200 km

10 a.m & 122 km

10:10 a.m & 210 km

11 a.m & 200 km

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Explanation:

When the second train departs Kolkata the first train covers 40 * 1 = 40 km
So, the distance between first train and second train is 40 km at 7.00am
Time taken by the trains to meet = Distance / relative speed
= 40 / (50 -40) = 4 hours
So, the two trains meet at 10 a.m.
The two trains meet 4 * 50 = 200 km away from Kolkata.