The age of mother one decade age was three times the age of her daughter 10 years hence mother rsquo...........

Quantitative Aptitude ( CCS) Problems based on Ages

The age of mother one decade age was three times the age of her daughter. 10 years hence, mother’s age will be two times that of her daughter. The proposition of their current ages is:

7:3

7:2

5:7

7:5

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Explanation:

Let, Ages of mother and daughter 1 decade ago was 3A and A years correspondingly
Then, (3A + 10) + 10 = 2 [(A + 10) + 10]
3A + 20 = 2A + 40
X = 20
Needed Ratio = (3A + 10) : (A + 10)
= 70 : 30
= 7 : 3