P and Q start simultaneously from a place A towards B 60 km apart P rsquo s speed is 5km h less than...........

Quantitative Aptitude ( CCS) Time & distance

P and Q start simultaneously from a place A towards B 60 km apart. P’s speed is 5km/h less than that of Q. Q, after reaching B, turns back and meets P at a places 20 km away from B. Q’s speed is:

8km/hr

12km/hr

6km/hr

10km/hr

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Explanation:

Solution:
Let the speed of P be x km/hr
then Q’s speed = (x+5) km/hr
Distance covered by Ajay = 60 + 20 = 80 km
Distance covered by Ravi = 60 – 20 = 40 km.
According to question,
80/(x+5) = 40/x
x = 5 km/hr.
then Q’s speed=5+5=10km/hr.