Two racers start running towards each other one from A to B and another from B to A They cross each ...........

Quantitative Aptitude ( CCS) Time & distance

Two racers start running towards each other, one from A to B and another from B to A. They cross each other after one hour and the first racer reaches B, 5/6 hour before the second racer reaches A. If the distance between A and B is 50 km. what is the speed of the slower racer?

15km/hr

20km/hr

25km/hr

30km/hr

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Explanation:

Solution:
Let second racer takes x hr with speed s2
First racer takes x-5/6 hr with speed s1
Total distance = 50km
S1 = 50/(x-(5/6))
S2= 50/x
As they cross each other in 1hr…
Total speed = s1 + s2
Now, T = D / S
50/(s1+s2) = 1
x = 5/2, 1/3
Put x= 5/2 in s2 –> 20km/hr