A train met with an accident 60km away from station A It completed the remaining journey at 5 6th of...........

Quantitative Aptitude ( CCS) Time & distance

A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

50km/hr

45km/hr

60km/hr

55km/hr

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Explanation:

Solution:
Let the original speed be 6x.
Travelling 60km at 5/6th of original speed cost 12 mins etc.
60/5x = 60/6x +12/60
==>x=10
Original speed 6x=60km/hr.