Hemant covers a certain distance with his own speed but when he reduces his speed by 10 km hr his ti...........

Quantitative Aptitude ( CCS) Time & distance

Hemant covers a certain distance with his own speed , but when he reduces his speed by 10 km/hr his time duration for the journey increases by 40 hrs, while if he increases his speed by 5km/hr from his original speed he takes 10hrs less than the original time taken . Find the distance covered by him.

1200km

1500km

1350km

1400km

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Explanation:

Solution:
Let distance be x km and speed be y km/hr
x/(y-10)-x/y=40==> x=4y(y-10) ——(1)
x/y-x/(y+5)=10==>x=2y(y+5) ——-(2)
Equate 1 and 2
4y(y-10)=2y(y+5)
2y-20=y+5==>y=25km/hr
Then x=2*25(25+5)=50*30=1500km