A man walk a certain distance and rides back in 4 hours 30 minutes he could ride both ways in 3 hour...........

Quantitative Aptitude ( CCS) Time & distance

A man walk a certain distance and rides back in 4 hours 30 minutes. he could ride both ways in 3 hours. The time required by the man to walk both ways is

5hrs10min

4hrs30min

6hrs

5hrs40min

Solution:
W+R = 4hrs 30min ie 9/2hrs = 4.5 hr-----(1)
R+R=3hrs==>R=1.5 hr----(2)

then , by subtracting eq. 2 from eq 1 :-
then W+R -R = 4.5-1.5 = 3 Hr.

for both side walk = 3+3 = 6 hours

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