Find the least number which when divided by 16 18 20 and 25 leaves 4 as remainder in each case...........

Quantitative Aptitude ( CCS) LCM, HCF

Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case but when divided by 7 leaves no remainder.

8004

13004

18004

18014

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Explanation:

L.C.M. of 16,18,20 and 25 = 3600
So, the required number will be in the form (3600*x) + 4
by putting x = 1, 2, 3, 4.........n.
At x = 5
⇒ (3600*5) + 4
⇒ 18000 + 4
⇒ 18004 is the smallest number which exactly divisible by 7 and will
leave 4 as remainder when it will be divided by 16,18,20 and 25.