M and N can do a piece of work in 30 days while N and O can do the same work in 24 days and O and M ...........

Quantitative Aptitude ( CCS) Time and work

M and N can do a piece of work in 30 days, while N and O can do the same work in 24 days and O and M in 20 days. They all work together for 10 days when N and O leave. How many days more will M take to finish the work?

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Explanation:

Solution:
2(M+N+O)’s 1 day work = (1/30+1/24+1/20)=1/8
=>(M+N+O)’s 1 day’s work= 1/16
work done by M, N and O in 10 days= 10/16=5/8
Remaining work= (1 – 5/8)
M’s 1 day’s work = (1/16 – 1/24)=1/48
Now, 1/48 work is done by M in 1 day.
So, 3/8 work wil be done by M in 48*3/8 = 18 days