M can do a piece of work in 10 days working 10 hours a day The work is started by M and on the secon...........

Quantitative Aptitude ( CCS) Time and work

M can do a piece of work in 10 days working 10 hours a day. The work is started by M and on the second day one man whose capacity to do the work is twice that of M, joined. On the third day another man whose capacity is thrice that of M, joined and the process continues till the work is completed. In how many days will the work be completed, if everyone works for five hours a day?

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Explanation:

Solution:
M total work 10*10=100
1st day =5hrs
2nd day =10+5=15
3rd day =15+10+5=30
4th day =20+15+10+5=50
Total (5+15+30+50) = 100
So 4th day they completed the work.