A cat is 50 of its own leaps behind a rat The cat takes 5 leaps per minute to the rat rsquo s 4 leap...........

Quantitative Aptitude ( CCS) Time & distance

A cat is 50 of its own leaps behind a rat. The cat takes 5 leaps per minute to the rat’s 4 leaps. If the cat and the rat cover 8m and 5m per leap resp., what distance will the cat have to run before it catches the rat?

800m

1100m

900m

600m

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Explanation:

Solution:
Speed of cat = 40m/min.
Speed of rat =20m/min.
Relative speed = 40 – 20 = 20m/min.
Diff. in dist. = 50 * 8 = 400m
Time in catching the rat = 400/20 = 20min.
Dist. traveled in 20min. = 20 * 40 = 800m