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A student walks from his house at a speed of 2(1/2)km per hour and reaches his school 6minutes late. The next day he increases his speed by 1kmph and reaches 6minutes before school time. How far is the school from his home?
5/4km
9/4km
7/4km
11/4km
Solution: S1*S2/difference of speed *(( late + early)/60) = (5/2 * 7/2)/1 * 12/60= 7/4km
By: Pranav Gupta ProfileResourcesReport error
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