Time & distance

Quantitative Aptitude ( CCS)

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A student walks from his house at a speed of 2(1/2)km per hour and reaches his school 6minutes late. The next day he increases his speed by 1kmph and reaches 6minutes before school time. How far is the school from his home?

5/4km

9/4km

7/4km

11/4km

Explanation:

Solution:
S1*S2/difference of speed *(( late + early)/60)
= (5/2 * 7/2)/1 * 12/60= 7/4km

By: Pranav Gupta

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