After travelling two hours a train met with an accident due to this it stops for an hour After this ...........

Quantitative Aptitude ( CCS) Problems on trains

After travelling two hours a train met with an accident due to this it stops for an hour. After this the train moves at 66(2/3)% speed of its original speed and reaches to destination 3hour late. If the accident would occur at 200km ahead in the same line then the train reaches only 2.5hours late. Then find the distance of journey and the original speed of the train?

2400km,600kmph

1800km,300kmph

2400km,400kmph

1800km,200kmph

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Explanation:

Solution:
Due to 200km it saves 5hrs.
For 3hrs it has to run 200*2*3 =1200km
66(2/3)% = 2/3
. after………..normal
speed 2 : 3
time 3 : 2
. 3-2 =1.
1 =2 ( train stops for 1 hr out 3hrs. so 3-1 =2)
2 =4
1200/4 = 300kmph
so 2hr*300 = 600km
Now total distance = 1200 +600 = 1800km