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If a person cover a distance in 5/7th of his normal speed, then he will reach his destination 20minutes late. Find the usual time taken by him on his normal speed?
100min
50min
140min
70min
Solution: Shortcut : multiply numerator by time/difference Difference = 7-5 =2 Time = 20 5*20/2 = 50min
By: Pranav Gupta ProfileResourcesReport error
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