send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A train after travelling 50km met with an accident and then proceeds at 3/4th of its former speed and arrived at destination 35min late. Had the accident occurred 24km further, it would have reached the destination only 20min late. Find the normal speed of the train?
36kmph
40kmph
38kmph
24kmph
Solution: 20min = 24km 35min = 42km Now ratio of speed – normal ……………after accident 4………………………….3 Ratio of time – 3……………………4 . (+1) = 35 So 3 = 105 min 42/105*60 =24kmph
By: Pranav Gupta ProfileResourcesReport error
Access to prime resources
New Courses