Ravi and Ajay start simultaneously from the same place A far B 50km apart Ravi rsquo s speed is 5km ...........

Quantitative Aptitude ( CCS) Time & distance

Ravi and Ajay start simultaneously from the same place. A far B 50km apart. Ravi’s speed is 5km/h less than that of Ajay. Ajay after reaching B, returns and meet Ravi at a place 10km apart from B. find Ravi’s speed?

10km/h

15km/h

12km/h

20km/h.

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Explanation:

Solution:
In the whole journey Ajay covers 20km more than Ravi .
Then time taken by Ajay = 20/5= 4hrs (Because in every hour Ajay covers 5km more than Ravi for 20 km.)
So
Speed of Ajay = 60/4 =15
Ravi’s speed = 15-5= 10km/hr