A man covers a distance in four equal parts He covers first part with speed of 60 kmph second part w...........

Quantitative Aptitude ( CCS) Time & distance

A man covers a distance in four equal parts. He covers first part with speed of 60 kmph, second part with 80 kmph and third part and fourth part with 120 kmph and 80 kmph respectively. Find the average speed of his journey.

60 kmph

80 kmph

120 kmph

100 kmph

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Explanation:

Solution:
|—–x——|——-x——–|——-x——-|——-x——-|
60 80 120 80
Let x= 240 km (LCM of speed)
Time= 240/60 +240/80 +240/120 +240/80=4+3+2+3=12 hours
Avd speed=total distance/ total time=240*4/12= 80 kmph