A B and C individually can do a certain piece of work in 35 42 and 24 days resp They started working...........

Quantitative Aptitude ( CCS) Time and work

A,B and C individually can do a certain piece of work in 35,42 and 24 days resp. They started working together but after ‘x’ days A and C left the job and the remaining work is completed by B with 25% more efficiency. If the whole work is completed in 114/5 days then find the value of x.

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Explanation:

Total work (LCM of 35, 42 and 24) = 840 units
Amount of work done by A,B and C = 24 , 20 and 35 units
Amount of work done by A, B and C together in ‘x’ days
= (24+20+35)*x = 79x units
Amount of work done by B alone in one day after increased efficiency = 20*1.25 = 25 units
Amount of work done by B alone in {(114/5) – x} days with increased efficiency = {(114/5) – 5} * 25
= (570 – 25x) units
79x + 570 – 25x = 840
=> x = 5