A can do a work in 24 hours while B can do the work in 18 hours Efficiency of C is 500 7 more than t...........

Quantitative Aptitude ( CCS) Time and work

A can do a work in 24 hours while B can do the work in 18 hours. Efficiency of C is 500/7% more than that of A and B when working together then find out the time taken by C alone to complete the work.

3 hours

6 hours

4 hours

8 hours

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Explanation:

Total work (LCM of 24 and 18) = 72 units
Work is done by A in one hour = 72/24 = 3 units
Work is done by B in one hour = 72/18 = 4 units
Work is completed by A and B together in one hour = 3+4 = 7 units
Number of units of work is completed by C in one hour = 7 + 71(3/7)% of 7 = 7+5 = 12 units
Required time taken by C alone to complete the work = 72/12 = 6 hours