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Two pipes A and B, one pipe can fill a tank 6 times as fast as another pipe. If together the two pipes can fill the tank in 22 minutes. How much time taken by the slower pipe alone will be able to fill the tank.
140 minute.
132 minute.
154 minute.
Let faster pipe alone can fill the tank in x minutes. Then, slower pipe alone can fill the tank in 6x minutes 1/x+1/6x = 22 6x/7 = 22 x = (22×7)/6 = 154/6 Required time = 6x = 154 minutes
By: Pranav Gupta ProfileResourcesReport error
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