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All the numbers from 105 to 498 are listed down in the ascending order. Ramu picks up every seventh number starting from 105 and prepares a list of these numbers. Ramu's assistant sums up all the numbers in this list. What is the total sum so obtained?
11757
17757
17157
71157
first digit=105 105,112,119.... Tn=a+(n-1)d = 105+(n-1)7 here for n=57 ,,last digit will be 497,, beyond n=57,,,d value of Tn will go beyond 498,,dat is nt allowed,, so sum will be Sn=n/2(2a+(n-1)d) 57/2(210+7(56)) 17157
Hence, option 3 is the correct answer.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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