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What is the remainder when 1! + 2! + 3! + … + 100! Is divided by 5?
1
3
5040
none of these
1!+2!+3!+...+100! = 1!+2!+3!+4!+ integers divisible by 5 = 1+2+6+24+ integers divisible by 5 = 33 + integers divisible by 5. So when 1!+2!+3!+...+100 is divided by 5, the remainder is the same as when 33 is divided by 5. 6 5)33 30 3 Hence,option 2 is the correct answer.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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