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If each of the three nonzero numbers a, b and c is divisible by 3, then abc must be divisible by which one of the following the numbers?
8
27
81
121
Since each one of the three numbers a, b, and c is divisible by 3,
the numbers can be represented as 3p,3q and 3r, respectively, where p,q and r are integers.
The product of the three numbers is 3p×3q×3r=27(pqr) Since p,q and r are integers, pqr is an integer and therefore abc is divisible by 27.
Hence, option 2 is the correct answer.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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