send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A Man took the car and travel from Bangalore to Mangalore by his car at the speed of 30 km//hr and then, the same distance he travelled on his bicycle at the speed of 20 km/hr from Mangalore to Mysore. Then he returned from Mysore to Bangalore via Mangalore at the speed of 16 km/hr on his foot. The average speed of the whole journey is:
20km/hr
21.5km/hr
22km/hr
19.2 km/hr
Solution: The distance between Bangalore and Mangalore is equal to distance between Mangalore and Mysore. So the average speed is 2*30*20/(20+30)=24km/hr Again he return from same route the distance is same Then the average is 2*24*16/(24+16)=19.2km/hr
By: Pranav Gupta ProfileResourcesReport error
Access to prime resources
New Courses