A batsman played three matches in a tournament The respective ratio between the scores of 1st and 2n...........

Quantitative Aptitude ( CCS) Average

A batsman played three matches in a tournament .The respective ratio between the scores of 1st and 2nd matches was 5 :4 and that between the scores of 2nd and 3rd matches was 2 :1 .The difference between the 1st and 3rd matches was 48 runs . What was the batsman’s average score in all the three matches ?

42(1/2)

58(2/3)

49(4/7)

52(1/3)

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Explanation:

Solution:
Match 1 : Match 2 = 5 :4
Match 2 : Match 3 = 2 : 1 = 4 :2
Therefore ,
Match 1 :Match 2 :Match 3 = 5 :4 : 2
Now ,
5x – 2x = 48
=> x= 16
Total runs scored in three matches = 5x + 4x +2x =11x
= 11 * 16 = 176
Required average = (176/3) =58(2/3)