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If the two digits of the age of Mr. X are reversed then the new age so obtained is the age of his wife. 1/11 of the sum of their ages is equal to the difference between their ages. If Mr. X is elder than his wife then find the difference their ages.
10yrs
13yrs
12yrs
9yrs
Solution: Let the two digit no be 10x+y,and reverse is 10y+x (10x + y + 10y + x) / 11 = 10x + y -10y-x x + y = 9x – 9y x/y = 5/4. Then Diff of two number is (10x + y) – (10y – x) = 9x – 9y Substitute x and y here. = 9(5-4) = 9 yrs.
By: Pranav Gupta ProfileResourcesReport error
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