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In a family, a couple has a son and daughter. The age of the father is four times that of his daughter and the age of the son is half of his mother. The wife is ten years younger to her husband and the brother is six years older than his sister. What is the age of the mother?
34
40
38
42
Solution: Let the daughter’s age be x years. Then, father’s age = 4x. Mother’s age = 4x – 10; Son’s age = x + 6. So, x + 6 = (4x-10)/2 ==> x=11. Therefore Mother’s age = 4X – 10= 44 – 10 = 34 years.
By: Pranav Gupta ProfileResourcesReport error
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