A man leaves from point A at 4 AM and reaches point B at 6 AM Another man leaves from point B at 5 A...........

Quantitative Aptitude ( CCS) Time & distance

A man leaves from point A at 4 AM and reaches point B at 6 AM. Another man leaves from point B at 5 AM and reaches point A at 8 AM. Find the time when they meet.

6:20 AM

6:15 AM

5:45 AM

5:36 AM

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Explanation:

Solution:
Use formula:
4 AM + (6-4)*(8-4)/[(6-4)+(8-5)]
gives 4 AM + 8/5
8/5 hours = 1 3/5 hours = 1 3/5*60 = 1 hour 36 minutes
So 4 AM + 1 hour 36 minutes = 5:36 AM