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2 towns A and B are 300 km apart. 2 trains start travelling from town A towards town B such that the second train leaves 8 hours late than the first one. They both arrive at town B simultaneously. If the speed of the faster train is 10 km/hr more than the speed of the slower train, find the time taken by the slower train to complete the journey.
25 hours
22 hours
14 hours
Cannot be determined
Solution: Let speed of the slower train is x km/hr, then speed of faster is (x+10) kmph. Let faster train takes t hours to cover the distance 300 km, then slower one takes (t+8) hours. Distance is same. So x/(x+10) = t/(t+8) Solve, 4x = 5t so , cannot be determined
By: Pranav Gupta ProfileResourcesReport error
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