From point A Priya and Bhavna start cycling towards point B which is 60 km away from A The speed of ...........

Quantitative Aptitude ( CCS) Time & distance

From point A, Priya and Bhavna start cycling towards point B which is 60 km away from A. The speed of Priya is 10 km/hr more than the speed of Bhavna. After reaching point B, Priya returns towards point A and meets Bhavna 12 km away from point B. Find the speed of Bhavna.

40 km/hr

15 km/hr

30 km/hr

20 km/hr

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Explanation:

Solution:
Speed of Bhavna = x km/hr, of priya = (x+10) km/hr
Distance covered by Priya = 60+12 = 72 km
And by Bhavna = 60-12 = 48 km
So
72/(x+10) = 48/x
Solve, x = 20