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The distance between two stations P and Q is 240 km A train starts from P towards Q and another train from Q to P at the same time and they meet after 8 hours. The train travel traveling from P to Q is slower by 6 kmph compared to another train from B to A, then find the speed of the slower train?
12 kmph
15 kmph
20 kmph
13 kmph
Solution: Speed of slower train = x Speed of faster train = x+6 Relative speed = 2x + 6 240/2x + 6 = 8 240 = 16x – 48 16x = 192 x = 12 kmph
By: Pranav Gupta ProfileResourcesReport error
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