Three men A B and C working together can do a job 6 hours less time than A did alone 1 hour less tim...........

Quantitative Aptitude ( CCS) Time and work

Three men A ,B and C working together can do a job 6 hours less time than A did alone ,1 hour less time than B alone and half the time needed by C .In how many days will A finish the work alone ?

20/3 days

23/4 days

22/5 days

33/6 days

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Explanation:

Solution:
A+B+C A B Cx hr.

x+6 x+1 2x Taking LCM = 2x (x+1)(x+6)
Taking efficiency of A and B ;
2x(x+1)(x+6)/(2x2 +2x+2x2 +12x) = 2x/1
3x2 +7x-6=0
X=-3(ignore)
X=2/3
A will finish its work in (x+6)=20/3 days