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Quantity I: A, B and C can do a certain piece of work in 24, 20 and 36 days resp. They started working together but after 5 days left the work and A left the work before 7 days of the completion of the work. If the work is completed in x days. Find the value of x.
Quantity II: 6 years ago, the ratio of the age of the Harish to that of Hari was 4:3 resp. After 15 years, the ratio of the age of Hari to that of Harish will become 13:15 resp. If the present age of Sahil is ‘y’ years and he is 8 years younger than Hari. Find the value of y.
Quantity I >= Quantity II
From I: Total work = 360 units Work done by A in a day = 15 units Work done by B in a day = 18 units Work done by C in a day = 10 units Total work in first five days = 43*5 = 215 units Total work by C in last 7 days = 10*7 = 70 units Remaining work = 360 – (215 + 70) = 75 units 75 units of work done by A and C = 75/25 = 3 days Total time to complete the work = 5+7+3 = 15 days From II: (4x+21)/(3x+21) = 15/13 => x = 6 Present age of Harish = 4x+6 = 30 years y = 24 – 8 = 16 Quantity I < Quantity II
Hence, option 4 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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