Quantity I The length of a rectangular field twice the side of a square field The cost of watering t...........

Quantitative Aptitude ( CCS) Arithmatic inequalities

Quantity I: The length of a rectangular field twice the side of a square field. The cost of watering the square field at Rs.8 per m^2 is Rs.X. The cost of watering the rectangular field at Rs. 6 per m^2 is Rs. 6000.

Quantity II: Seeta and Geeta start a business together with ratio of investment as 5:4. The profit of Geeta out of total profit of Rs.3600 is Rs.Y and 25% of the profit is given to Geeta for taking care of all the marketing work.

Quantity II > Quantity I

No relation.

Quantity I < Quantity II

Quantity I > Quantity II

Quantity I >= Quantity II

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Explanation:

From I: Area of the rectangular field = 6000/6
= 1000 m^2
Let length be x and breadth be (x-15) m.
Now, x(x-15) = 1000
=> x = 40
side of square field = 40/2 = 20 m
20*20 * 8 = x
=> x = Rs.3200
From II: Profit received by Geeta = 0.25*3600 = Rs.900
Remaining profit = 3600 – 900 = Rs.2700
Profit share of Geeta in remaining profit = 4/9*2700 = Rs.1200
Total profit share of Geeta = 1200+900 = Rs.2100
Quantity I > Quantity II

Hence, option 4 is the correct answer.