A thief ran away from a police station situated in Shivgarh towards Goa city at 3 am with a speed of...........

Quantitative Aptitude ( CCS) Arithmatic inequalities

A thief ran away from a police station situated in Shivgarh towards Goa city at 3 am with a speed of 40 km/hr. Inspector realised the breakdown at 6 am and started chasing the thief with speed of 60 km/hr. The distance between Shivpuri and Goa is 480 km.

Quantity I: At what distance from Goa, Inspector will catch the thief?

Quantity II: If Inspector would have realised the breakdown at 4:30 am, then at what distance from Shivgarh, would Inspector have caught the thief?

I < II

I =< II

I = II

I > II

I >=II

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Explanation:

From I: Dist. Travelled by thief when police realised the breakdown = 3*40 = 120 km
Time taken by police to chase the thief = 120/(60-40) = 60 hour
Dist. Travelled by Police = 480 – 360 = 120 km
From II: Dist. Travelled by thief when police realised the breakdown = 1.5*40 = 60 km
Time taken by police to chase the thief = 60/(60-40) = 3 hours
Required distance = 3*60 = 180 km
I < II

Hence, option 1 is the correct answer.