Arun is 50 more efficient than Aman and Anil is 40 less efficient than Arun The time taken by Anil a...........

Quantitative Aptitude ( CCS) Arithmatic inequalities

Arun is 50% more efficient than Aman and Anil is 40% less efficient than Arun. The time taken by Anil alone to complete the work is 2 days more than the time taken by Aman alone to complete the work.

Quantity I: Find the time taken by Arun to complete 60% of the work with 60% of his original efficiency.

Quantity II: Find the time taken by Anil to complete 40% of the work with 80% of his original efficiency.

I > II

I = II

I >=II

I < II

I =< II

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Explanation:

Let the time taken by Aman to complete the work be x days.
Time taken by Arun to complete the work = x/1.5 days
Time taken by Anil to complete the work = (x/1.5)/0.6 = x/0.9 days
Now, x/0.9 = x+2
=> x = 18 days
Time taken by Arun to complete the work = 18/1.5 = 12 days
Time taken by Anil to complete the work = (x/1.5)/0.6 = 18/0.9 = 20 days
From I: Time taken Arun to complete 60% of the work with 60% of his efficiency = 12/0.6*0.6 = 12 days
From II: Time taken by Anil to complete 40% of the work with 80% of his efficiency = 20/0.8*0.4 = 10 days
I > II

Hence, option 1 is the correct answer.