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The perimeter of a square is equal to twice the perimeter of a rectangle of length 11 cm & breadth 10 cm
Quantity I:Find the circumference of a semicircle whose diameter is equal to the side of the square.
Quantity II:Find the circumference of another semicircle whose radius is 14 cm
Quantity I > Quantity II
Quantity I ≥ Quantity II
Quantity II > Quantity I
Quantity II ≥ Quantity I
Quantity I = Quantity II or Relation cannot be established
Perimeter of square= 2* perimeter of rectangle
4a=2*(2(l+b))4a
=4*(11+10)a=21
Circumference of semicircle= πr+d
Hence, option 3 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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