Find the present age of A Quantity I Three years before the ratio of ages of A and B was 5 6 Three y...........

Quantitative Aptitude ( CCS) Arithmatic inequalities

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Find the present age of A

Quantity I: Three years before, the ratio of ages of A and B was 5:6. Three years hence this ratio will become 6:7

Quantity II: Eleven years before the ratio of ages of A and B was 1:3 and eleven years hence the ratio will become 1:2

Quantity I > Quantity II

Quantity I ≥ Quantity II

Quantity II > Quantity I

Quantity II ≥ Quantity I

Quantity I = Quantity II or Relation cannot be established

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Explanation:

Quantity I:                   A                B
3 years before             5                6
3 years after                6                7
Difference in both case 6-5=1 and 7-6=1
1=6
6=30
Present age =30+3=33
Quantity II:                   A                B
11 years before             1                3
11 years after                1                2
Difference A=1-1=0 ; B= -1
To make the difference same; multiply equation 2 by 2; we get
Quantity II:                   A                B
11 years before             1                3
11 years after                2                4
Difference A=2-1=1; B=4-3=1
1=2
11=22
Present age= 22+11=33