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Quantity 1:Find the area of the trapezium whose parallel sides are 15cm and 12 cm and the perpendicular distance between them is 19cm.
Quantity 2:Find the area of the quadrilateral piece of ground one of whose diagonal is 15 cm long and the perpendicular from the other two vertices are 12cm and 9cm respectively.
Quantity 1 ≥ Quantity 2
Quantity 1 = Quantity 2 (or) No relation
Quantity 1 > Quantity 2
Quantity 1 ≤ Quantity 2
Quantity 1 < Quantity 2
Quantity 1:
Area of the Trapezium=1/2(Sum of the parallel sides)×(Perpendicular distance between them)
=1/2(12+15)×19
=1/2(27×19)
=256.5 cm2
Quantity 2:
Area of the quadrilateral =1/2×d×(h1+h2)
d=15cm
h1=12cm
h2=9cm
Area=1/2×15(12+9)
=1/2×15(21)
=315/2=157.5 cm2
Hence Quantity 1>Quantity 2
Hence, option 3 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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