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A bag contains a total of (x+6) balls of three colors of Black, White and Brown such that the ratio of number of White and Brown balls is 3:4 resp. and the probability of drawing a Black ball is 1/3. Find the number of balls in the bag.
Statement I: Probability of drawing a white ball is (2/7).
Statement II: The number of Black balls in the bag is 2 less than the number of Brown balls.
Either I or II
Let the number of White and Brown color balls be 3k and 4k resp. So, the number of Black balls = (x+6) – (3k+4k) = (x – 7k +6) Probability of drawing Black balls = 1/3 (x – 7k +6)/(x+6) = 1/3 => 21k = 2x+12 –(1) From I: Probability of drawing a white ball = 2/7 3k/(x+6) = 2/7 => 21k = 2x+12 –(2) Both the equations are same. So, this statement is not sufficient. From II: (x – 7k + 6) = 4k – 2 => x = 11k – 8 –(3) From (1) and (3), we get 21k – 12 = 22k – 16 => k = 4 So, x = 11*4 – 8 = 36 Therefore, the total number of balls = 36 + 6 = 42 Hence, this statement is sufficient alone.
Hence, option 3 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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