A is 20 more efficient than B and 50 more efficient than C if they together can do a work in 24 days...........

Quantitative Aptitude ( CCS) Time and work

A is 20% more efficient than B and 50% more efficient than C. if they together can do a work in 24 days then find in how many days B alone can do the work?

60days

72days

90days

180days

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Explanation:

Solution:
A ………B | A………C
Efficiency 6……….5 | 3………2
Days 5……….6 | 2………3
Days A : B : C
. 10 12 15
A = 10……….6
B = 12………..5 …. (LCM = 60)
C = 15………..4
A+B+ C = 15
60/15=4
4=24
1= 6
B=12= 12*6 = 72days