X and Y stand in a line at random with 5 other people Quantity I Probability that there are 3 people...........

Quantitative Aptitude ( CCS) Arithmatic inequalities

X and Y stand in a line at random with 5 other people

Quantity I: Probability that there are 3 people between X and Y

Quantity II: Probability that at least one from A or B qualifies the exam when probability of A qualifying the exam is 0.3 and probability of B qualifying the exam is 0.4

Quantity I > Quantity II

Quantity I ≥ Quantity II

Quantity II > Quantity I

Quantity II ≥ Quantity I

Quantity I = Quantity II or Relation cannot be established

छोटे Courses बड़े Results

Master Arithmatic inequalities

Prepare through Micro-courses

Try Now

Explanation:

I: There are 7 people in total including X and Y; consider 7 position numbered 1,2,….,6,7
When X is at 1, then Y is at 5 or vice versa; When X is at 2, Y is at 6 or vice versa and When X is at 3 then Y is at 7. Means there are 3 possible seating arrangement for X and Y when there is a gap of 3 people between them.
total ways of X and Y sitting in any two position = 7C2= 21
P=3/21=1/7II: P(either)= [1-P(None)]= [1-P(not A)*P(not B)]=[1- (0.7*0.6)]
=0.56
II>I

Hence, option 3 is the correct answer.